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6n^2=14-5n
We move all terms to the left:
6n^2-(14-5n)=0
We add all the numbers together, and all the variables
6n^2-(-5n+14)=0
We get rid of parentheses
6n^2+5n-14=0
a = 6; b = 5; c = -14;
Δ = b2-4ac
Δ = 52-4·6·(-14)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-19}{2*6}=\frac{-24}{12} =-2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+19}{2*6}=\frac{14}{12} =1+1/6 $
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